Qwertyuiop[]
Junior Member
- Joined
- Jun 1, 2022
- Messages
- 123
Hi, i have this equation of degree 5. The equation is [math](x^5 - 4x^3)^2 =0[/math]
I did it like this , i just need to know if i did it right. So i factor out x^3 and we get: [math](x^3(x^2-4))^2 = 0[/math]I took the square root of both sides and set equal to 0 and got x=0 , x=2 , x=-2.
The other way is to expand but i get an equation of degree 10 and it gets a little complicated. How would you solve this, by factoring out the x^6 ?
This is the expanded form : x^10 - 8(x^8) + 16(x^6)= 0
I did it like this , i just need to know if i did it right. So i factor out x^3 and we get: [math](x^3(x^2-4))^2 = 0[/math]I took the square root of both sides and set equal to 0 and got x=0 , x=2 , x=-2.
The other way is to expand but i get an equation of degree 10 and it gets a little complicated. How would you solve this, by factoring out the x^6 ?
This is the expanded form : x^10 - 8(x^8) + 16(x^6)= 0