I tried solving this problem, and got this. The answer is this: I'm not sure where I went wrong.
X xxMsJojoxx Junior Member Joined Oct 6, 2020 Messages 54 Oct 31, 2020 #1 I tried solving this problem, and got this. The answer is this: I'm not sure where I went wrong.
Dr.Peterson Elite Member Joined Nov 12, 2017 Messages 16,089 Oct 31, 2020 #2 Looks right to me, except that you have to write the pairs, as sometimes not every y goes with every x. Did you rationalize the denominators, to see that [MATH]\sqrt{\frac{1}{2}} = \frac{1}{\sqrt{2}} = \frac{\sqrt{2}}{2}[/MATH]?
Looks right to me, except that you have to write the pairs, as sometimes not every y goes with every x. Did you rationalize the denominators, to see that [MATH]\sqrt{\frac{1}{2}} = \frac{1}{\sqrt{2}} = \frac{\sqrt{2}}{2}[/MATH]?