substitution

[xxchorkyxx]

if abc=40 then what is (-5c)(b/3)(6a)
I'm mostly stumped on the multiplication of a fraction but could use guidance for the rest of the equation too.

 

[Dr.Peterson]

Let's see where you're stumped. You need first to simplify [MATH]-5c\cdot\frac{b}{3}\cdot 6a[/MATH]. Do you see that you can rewrite that as [MATH]\frac{-5c}{1}\cdot\frac{b}{3}\cdot \frac{6a}{1}[/MATH]? What can you do next?