A cylindrical water tank, [MATH]5m[/MATH] radius, [MATH]20m[/MATH] height is being drained at the bottom of the tank. The amount of water released with average speed [MATH]0.5\sqrt{h}[/MATH] (h is the height of the water tank). Ask after how long the tank will run out?
Some answers are given:
a) 20 hours
b) 620 minutes
c) 400.862 minutes
d) 1404.962 minutes
My method is as follows: [MATH](\pi∗5^{2}∗20)/(0.5\sqrt{20})=702.481[/MATH] minutes
I do not know where was wrong. Looking forward to your help. Thanks!
Some answers are given:
a) 20 hours
b) 620 minutes
c) 400.862 minutes
d) 1404.962 minutes
My method is as follows: [MATH](\pi∗5^{2}∗20)/(0.5\sqrt{20})=702.481[/MATH] minutes
I do not know where was wrong. Looking forward to your help. Thanks!