Is this what you are talking about?[MATH]x_1^2 = \frac{a^2 + b^2 \pm \sqrt{a^4+2a^2b^2+b^4 – 4a^3b + 4ab^3}}{2(a^2 – b^2)}[/MATH]
\displaystyle \(\displaystyle x_1_2 = \frac{a^2 + b^2 \pm \sqrt{a^4+2a^2b^2+b^4 – 4a^3b + 4ab^3}}{2(a^2 – b^2)}[\MATH][\MATH]
Yes this is what I meant but not x1 squaredIs this what you are talking about?
Try hitting “preview” before hitting “post.”
Use:Yes this is what I meant but not x1 squared
OK. We NOW know that is not the left hand side of the equation. Would you like to disclose what IS the left hand side, or shall I keep making guesses?Yes this is what I meant but not x1 squared
It is the quadratic formulaOK. We NOW know that is not the left hand side of the equation. Would you like to disclose what IS the left hand side, or shall I keep making guesses?
Perhaps x_1_2 means [MATH]x^{12}.[/MATH]
This may take a while if you continue so coy about saying what the equation actually is. There are an infinite number of things that it may not be.
I assume it is:It is the quadratic formula
Hi Albi. We call that one the "radicand".… Can someone tell me what can I do with the [expression] in the square root.
The left hand side is not the quadratic formula. Did Subhotosh Khan guess correctly what you meant?It is the quadratic formula
YesThe left hand side is not the quadratic formula. Did Subhotosh Khan guess correctly what you meant?
(a² -b²)x² -(a² +b²)x +ab = 0Then Otis and the Khan of Khans have already given you two suggestions for simplifying. Furthermore, I wonder whether you have reached the correct intermediate stage. You have not told us what led you to this rather messy equation.
[MATH][/MATH]