A swimmer covers a distance of 112 miles on both legs . If he faces a negative tide of 3 miles per hr on the out section & the reverse on the inwards stage & takes a total of 22 hrs , what was his average speed ?
Is there a formula involving ( distance = speed * time ) that takes account of the tidal action ? 112 = ( S - 3 ) * 22 ; S = ( speed ) ? Thank you .
Is there a formula involving ( distance = speed * time ) that takes account of the tidal action ? 112 = ( S - 3 ) * 22 ; S = ( speed ) ? Thank you .