Verify that the given function is a solution of the differential equation:
x^2 + y^2 = cy ; y' = (2xy)/(x^2 - y^2)
Here's what i've done:
Implicit differentiation on LHS: 2x + 2y(dy/dx) = c
The c im assuming is just a constant??
Now however i manipulate that i cant make it equal to y' = (2xy)/(x^2 - y^2)
x^2 + y^2 = cy ; y' = (2xy)/(x^2 - y^2)
Here's what i've done:
Implicit differentiation on LHS: 2x + 2y(dy/dx) = c
The c im assuming is just a constant??
Now however i manipulate that i cant make it equal to y' = (2xy)/(x^2 - y^2)