If -1< a< 2 then -2< a- 1<1 so \(\displaystyle 1< (a- 1)^2< 4\) and -3< a- 2< 0 so \(\displaystyle 0< (a- 2)^2< 4\).
I don't see how that can come out to a single number!
ahhhhhhhhhhhhhh i see, so i have to use the definition of abs value, using the domain it ends a+1 + -a+2 it cancels and the answer is 3 !! many thanks hallsoflvy and pka : )
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