ALIAHMAD
New member
- Joined
- Jul 5, 2022
- Messages
- 21
if [(sinx)^4]/2 + [(cosx)^4]/3 = 1/5
then
prove that (tanx)^2=2/3
I tried solving this as follows
taking LCM as 6
{3[(sinx)^4] + 2[(cosx)^4]}/6=1/5
{3[(sinx)^4] + 2[(cosx)^4]}=6/5
now using sin^n+cos^n=1 property
(sinx)^4 + 2=6/5
(sinx)^4=-4/5
but -ve should not come there as sin is raised to 4th power
what I did wrong ?
then
prove that (tanx)^2=2/3
I tried solving this as follows
taking LCM as 6
{3[(sinx)^4] + 2[(cosx)^4]}/6=1/5
{3[(sinx)^4] + 2[(cosx)^4]}=6/5
now using sin^n+cos^n=1 property
(sinx)^4 + 2=6/5
(sinx)^4=-4/5
but -ve should not come there as sin is raised to 4th power
what I did wrong ?