What is the missing value in the equation?

eddy2017

Elite Member
Joined
Oct 27, 2017
Messages
2,525
Hi,
seems simple but it is not for me. I am trying to find somethinig that fits the answer given but nothing so far.
is there a way to start attacking this problem quickly without so much trying?
thanks in advance for any hint,
eddy

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simplifying both sides
[math]2 3/12 + x = 25/8[/math][math](9/4)x= 21/8[/math]clearing the x by multiplying by the multiplicative inverse
[math](4/9) * (9/4)x = (4/9)* (21/8)[/math][math]7/6 = 1 1/6[/math]
 
so the missing value is 6?.
But the result is 1 1/6
so when I replace the value found for x doesn't equate to 2 5 /8 ??
 
simplifying both sides
[math]2 3/12 + x = 25/8[/math][math](9/4)x= 21/8[/math]clearing the x by multiplying by the multiplicative inverse
[math](4/9) * (9/4)x = (4/9)* (21/8)[/math][math]7/6 = 1 1/6[/math]
[imath]2\frac{3}{12}\neq \frac{23}{12}[/imath] and [imath]2\frac{5}{8}\neq \frac{25}{8}[/imath]. Try again.
 
[math]2 3/12 + x = 2 5/8[/math]simplifying
[math]27/12 + x = 21/8[/math][math]9/4 + x = 21/8[/math]
now subtractin' 9/4 from both sides
[math]x + 9/4 - 9/4 = 21/8 - 9/4[/math]subtracting the fractions on the right hand side
[math]x =3/8[/math]
checking
[math]2 3/12 + 3/8 = 2 5/8[/math]simplifying
[math]2 1/4 + 3/8[/math][math]9/4 +3/8[/math][math]21/8[/math][math]= 2 5/8[/math]
 
[math]2 3/12 + x = 2 5/8[/math]simplifying
[math]27/12 + x = 21/8[/math][math]9/4 + x = 21/8[/math]
now subtractin' 9/4 from both sides
[math]x + 9/4 - 9/4 = 21/8 - 9/4[/math]subtracting the fractions on the right hand side
[math]x =3/8[/math]
checking
[math]2 3/12 + 3/8 = 2 5/8[/math]simplifying
[math]2 1/4 + 3/8[/math][math]9/4 +3/8[/math][math]21/8[/math][math]= 2 5/8[/math]
Eddy, you should learn how to write fractions in LaTex. Copy and paste the following line into the "Insert math" screen. Adapt a and b to your needs.
\frac{a}{b}
You are correct, [imath]x=\frac{3}{8}[/imath]. Now, compare that to the OP.
[math]\frac{3}{8}=\frac{3}{\square}[/math]
 
[math]\frac{5}{8}[/math]
 
Last edited by a moderator:
[math]$\frac{5}{8}$[/math]
You don't need the $ signs..........................................................................................[$ signs were removed from response #11]
You haven't answered your FIND. What's the value in the box?
 
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