sandra23860

06-15-2005, 09:41 PM

3<2-x<=5

4+1/2(x)=2

4+1/2(x)=2

View Full Version : solve inequalities

sandra23860

06-15-2005, 09:41 PM

3<2-x<=5

4+1/2(x)=2

4+1/2(x)=2

tkhunny

06-15-2005, 10:23 PM

3<2-x<=5

One piece at a time.

3 < 2-x

Add x

3+x < 2

Subtract 3

x < -1

2-x <= 5

Add x

2 <= 5+x

Subtract 5

-3 <= x

Intersection

-3 <= x < 1

Check

3<2-(-2)<=5 ??

3<2+2<=5 ??

3<4<=5 Looks good.

4+1/2(x)=2

Subtract 4

1/2(x)=-2

Multiply by 2

x = -4

Check

4+1/2(-4)=2 ??

4-2=2 ??

2 = 2 Looks good.

OK, now what was it you wanted? Where were you having trouble?

One piece at a time.

3 < 2-x

Add x

3+x < 2

Subtract 3

x < -1

2-x <= 5

Add x

2 <= 5+x

Subtract 5

-3 <= x

Intersection

-3 <= x < 1

Check

3<2-(-2)<=5 ??

3<2+2<=5 ??

3<4<=5 Looks good.

4+1/2(x)=2

Subtract 4

1/2(x)=-2

Multiply by 2

x = -4

Check

4+1/2(-4)=2 ??

4-2=2 ??

2 = 2 Looks good.

OK, now what was it you wanted? Where were you having trouble?

Powered by vBulletin® Version 4.2.3 Copyright © 2019 vBulletin Solutions, Inc. All rights reserved.