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I would probably choose to express the recursion in homogeneous form: 2a_{n+2}-3a_{n+1}+a_{n}=0 Then it's easy to see that the...

Mark, don't worry as things are always weird looking for Denise. I myself prefer to think that an+1= (an+1)/2

I would probably choose to express the recursion in homogeneous form: 2a_{n+2}-3a_{n+1}+a_{n}=0 Then it's easy to see that the...

Hint: This is a bit of a trick question...consider the poles moving closer and closer to each other. :)

Yes, if the cable is 80 m long, and goes down 40 m and then back up 40 m, then the poles must be at the same location, or 0 m apart.

I am impressed (OK shocked) that you know what a Catenary is.

Well, hello to you too! Are you asking what the shape of the cable is? If so, go here: https://en.wikipedia.org/wiki/Catenary

Mark, don't worry as things are always weird looking for Denise. I myself prefer to think that an+1= (an+1)/2

Gets kinda weird using Mark's formula: 65, 33, 17 ,9 ,5 ,3 ,2 , 3/2, 5/4, 9/8, 17/16, ....

Gets kinda weird using Mark's formula: 65, 33, 17 ,9 ,5 ,3 ,2 , 3/2, 5/4, 9/8, 17/16, ....

This a comment. I have no doubt that the problem means that we are to take the predictions as independent with probability 0.48...

Using (a), since d|3 then we can see that the only divisors of n+1 and n^2+2 are multiples of 3. But because n is a multiple of 3, n+1...

Hi guys, sometimes I find it hard to go to aspect of "superposition" of something , I mean for example v1+v2+v3+v4 which they are...

4 × 12 = 48, not 36. 😎

thanks alot!!!!