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• skeeter replied to the thread Convergence tests.
\displaystyle \lim_{n \to \infty} \dfrac{(2n+2)(2n+1)}{(n+1)^2} \div \left(\dfrac{n+1}{n}\right)^{2n} try again …
• canvas replied to the thread Convergence tests.
\text{let}\,\,\,a_n=\frac{(2n)!}{n^{2n}}\\\\\Rightarrow...
• blamocur replied to the thread Convergence tests.
The ratio test seems to work for me.
• blamocur replied to the thread proof.
Perfect!
• blamocur reacted to canvas's post in the thread proof with Like.
After some hard work guys I found the best solution for that, just look...
• BigBeachBananas replied to the thread Convergence tests.
Ratio tests are typically used for series with factorials because they cancel out nicely.
• BigBeachBananas reacted to skeeter's post in the thread Convergence tests with Like.
Try the ratio test?
• BigBeachBananas reacted to canvas's post in the thread proof with Like.
After some hard work guys I found the best solution for that, just look...
• canvas replied to the thread Convergence tests.
d'alembert test also means ratio test, just look what a horrible limit we'll get using this test... :/
• skeeter replied to the thread Convergence tests.
Try the ratio test?
• canvas posted the thread Convergence tests in Calculus.
Does the series converge or diverge? \sum_{n=1}^\infty\frac{(2n)!}{n^{2n}}\\\\\text{I tried to use d'alembert test but I got so hard...
• lev888 reacted to canvas's post in the thread proof with Like.
After some hard work guys I found the best solution for that, just look...
• canvas replied to the thread proof.
After some hard work guys I found the best solution for that, just look...
• BigBeachBananas replied to the thread Frustrum base problems.
You can, but you have to use a half-angle or double identity. Also, assuming you know the unit circle and radians...
• lev888 replied to the thread Frustrum base problems.
Look up tangent of half angle.