# Latest activity

• MarkFL replied to the thread Year 7 geometry help.
Hello, and welcome to FMH! :) What are your thoughts on the choices given?
• Just need help on this one.
• Otis replied to the thread The triangle midsegment theorem.
Hello. If you'd like to review some videos on this, you'll find some by googling keywords find vertices triangle given midpoints. Cheers 😎
• Otis replied to the thread Is this right?.
Silent? Next time, run outside naked and scream loudly. That's more fun. 😎
• Line up 50 oranges on your kitchen bench. Now take 25 away. How many oranges are left on the bench? Count them. 😎
• MarkFL replied to the thread The triangle midsegment theorem.
Let's plot those points and join them as follows: Now, one side of the triangle will have a side that passes through point $$K$$ and...
• Please scroll up. \;\uparrow\; ͏This post is for thread-bumping only. \;
• I don’t understand how to do this? If anyone could offer advice, I would appreciate it. I completely understand the mid segment theorem...
• topsquark reacted to MarkFL's post in the thread Resistance with Like.
Let's let $$R$$ be the resistance in ohms of the 1 m segment of wire, and $$D$$ is the diameter of the wire in mm. From the statement...
• Jomo replied to the thread algebra.
You divided 6 by 3 and got 2, ok. You divided 6 by 18 and got 3. Nope! 6/18 = 1/3. It is 18/6 = 3. In any case you should divide both...
• ksdhart2 replied to the thread Match the post#.
0 + 1 \cdot 2^3 \cdot 4 \cdot 5 \cdot 6 + 7 \cdot 8 + 9 = 1025 9 \cdot 87 + 6 + 5 \cdot 43 + 21 + 0 = 1025
• MarkFL replied to the thread Resistance.
Let's let $$R$$ be the resistance in ohms of the 1 m segment of wire, and $$D$$ is the diameter of the wire in mm. From the statement...
• jazz2112 posted the thread Resistance in Arithmetic.
I have no clue how to start this question. Question: The electrical resistance of 1 metre of a certain wire is directly proportional...
• Denis replied to the thread Match the post#.
0! + 1 + 2.3 + 4^5 + 6.7 - 8 - √9 = 1024 9 + 8 - 7 - 6 - 5 + 4 - 3 + 2^10 = 1024
• I do not know if I set up the actual equation correctly so any tips would help! Thanks! Cardioid: r=1+sin(theta) Here is my work, I...