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Definitely tell your teacher about it; but it is not unheard-of for instructional programs to be wrong occasionally. Ideally, I'd like...

Okay. Sure, let's do that. A few pages ago, there was a single sheet containing the pages 22 and 23.

What if the last page was torn - and it was printed (and counted) only on one side (i.e. the last printed page was an odd page).

I did check but I couldn't make the answer given, which was 72 for and equals of 22. Thank you - this is kind of good news AND bad news...

Saying that a continuously differentiable function is integrable does NOT imply that a function must be continuously differentiable...

Your thought process matches mine - AP. So how many pages did the original (intact) book had?

This is a faulty question. Pickup any book or magazine a single sheet is numbered with two integers, one odd & one even. The odd is less...

This formula applies to a valid sequence. Without 22 and 23 the sequence is not a valid arithmetic sequence. How do we make it valid...

I would let \(P\) be the number of pages originally in the book and write: 0<\frac{P(P+1)}{2}-7495<2P You should find two integer...

Tried to use a formula of sum ((1+n)/2)n=7495 although it doesn't seem correct at all

Did you consider checking the answer? 0.5(72- 32)= 0.5(40)= 20 NOT 22 so 72 is definitely not a solution to this equation. 0.5(76-...

What's the formula you are trying to use and how did you use it?

Your answer (76) is correct.

So I've got this problem: A sheet was torn from a book (which is e.g. pages 22,23). The sum of all the remaining pages is 7495. How many...

Here is what I would do, but is requires knowledge of complex numbers. For example the octagon is eight sides so look at the eight...