1. the square root of 7 times the square root of 18 over the square root of 2 = ?
I got 3 times the square root of 7.
Correct!
sqrt(18)sqrt(7) / sqrt(2)
= sqrt(9)sqrt(2)sqrt(7) / sqrt(2)
= sqrt(9)sqrt(7)
= 3sqrt(7)
2. the square root of 10 times the square root of 16 all over (divided by the square root of 5 = ?
I got 4 times the square root of 2.
Correct again!
sqrt(16)sqrt(10) / sqrt(5)
= 4sqrt(5)sqrt(2) / sqrt(5)
= 4sqrt(2)
3. 3 times the square root of 8 over 64...the book has the answer as 3 times the square root of 2 all divided by 4 but I get 3 times the aquare root of 8 all over 8?
Incorrect; how did you arrive at that?
3sqrt(8/64)
= 3sqrt(1/8)
= 3sqrt(1) / sqrt(8)
= 3 / sqrt(4)sqrt(2)
= 3 / 2sqrt(2)
Looks like your "book" went at it this way:
3sqrt(8/64)
= 3sqrt(8) / sqrt(64)
= 3sqrt(4)sqrt(2) / 8
= 3(2)sqrt(2) / 8
= 3sqrt(2) / 4
Both are correct; I don't know which is the most "proper";
perhaps someone else will enlighten us :?:
So I was previously wrong: you can't ask for a refund :shock: