How would you approach this question if you aren't given the standard deviation?
In a recent survey of 250 outpatients at a local hospital, it was found that 195 patients were satisfied with the level of care that they received. Find the 99% confidence interval for the proportion of all outpatients that were satisfied with the level of service received.
I know n=250 and p=195/250 =0.78
In a recent survey of 250 outpatients at a local hospital, it was found that 195 patients were satisfied with the level of care that they received. Find the 99% confidence interval for the proportion of all outpatients that were satisfied with the level of service received.
I know n=250 and p=195/250 =0.78