T_TEngineer_AdamT_T
New member
- Joined
- Apr 15, 2007
- Messages
- 24
find the general solution of:
\(\displaystyle (y+1)dx + (4x - y)dy = 0\)
then i put in standard form ...
\(\displaystyle \frac{dx}{dy} + \frac{4x}{1+y} = \frac{y}{y+1}\)
now im stuck... i know the integrating factor is \(\displaystyle (1+y)^4\)...
which i multiply the equation with
and im confused what to do next... i cant really hit the answer at the back of the book
\(\displaystyle 20x = 4y - 1 + c(y+1)^{-4}\)
\(\displaystyle (y+1)dx + (4x - y)dy = 0\)
then i put in standard form ...
\(\displaystyle \frac{dx}{dy} + \frac{4x}{1+y} = \frac{y}{y+1}\)
now im stuck... i know the integrating factor is \(\displaystyle (1+y)^4\)...
which i multiply the equation with
and im confused what to do next... i cant really hit the answer at the back of the book
\(\displaystyle 20x = 4y - 1 + c(y+1)^{-4}\)