Re: solving systems using elimination=(
sum_one said:
I have tried so hard to figure this one out, i just dont understand it :? .... plz help...
4x-3y =11 and 3x-5y = -11
I see no work - it would be helpful to see
what you have tried, so that we can correct you
You have a system of two linear equations
4x-3y =11
3x-5y = -11
You are allowed to multiply each equation by any constant (as long as you do it to both sides of the equal sign) so that you can add / subtract terms.
What could you multiply the top equation by so that one of the terms is equal to another term in the other equation?
If you want the 3y term in the top equation to = 5y, than what would you have to multiply by? Divide 5y by 3y and you get (5/3). Therefore, (5/3)(3y) = 5y
If you can get one term from one equation which appears in the other equation, than you can add or subtract them to cancel them out... or "eliminate" that term.
You can, of course, multiply by a number so that you don't have any fractional terms.
Understood?