bccrusader3
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- Aug 6, 2008
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120 people apply for two jobs. forty-eight of the applicants are women. if two applications are selected at random, what is the probability that only one is a woman's application?
Probability Q: 48 of 120 applicants are women
- Thread starter bccrusader3
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Hello, bccrusader3!
\(\displaystyle \text{There are: }\;{120\choose2} \:=\:7140\text{ possible selections.}\)
\(\displaystyle \text{To select one woman and one man, there are: }\:48\cdot72 \:=\: 3456\text{ ways.}\)
\(\displaystyle \text{Therefore: }\;P(\text{one woman}) \;=\;\frac{3456}{7140} \;=\;\boxed{\frac{288}{595}}\)
\(\displaystyle \text{There are: }\;{120\choose2} \:=\:7140\text{ possible selections.}\)
\(\displaystyle \text{To select one woman and one man, there are: }\:48\cdot72 \:=\: 3456\text{ ways.}\)
\(\displaystyle \text{Therefore: }\;P(\text{one woman}) \;=\;\frac{3456}{7140} \;=\;\boxed{\frac{288}{595}}\)