Petenerd said:
How can you graph this? Can you give me an equation like y = \(\displaystyle \frac 2 3\)x + 6?
1. The line having slope -3 and containing the point (-6,5)
2. The line having slope \(\displaystyle \frac 2 3\) and containing hte point (0,4)
They give you the slope and a point in each case. To graph a line in this situation, you can either find the equation first, or plot another point first.
To plot another point: In question #1, your given point is (-6,5) and slope is -3. Slope means rise over run or y/x. So this means for every 1 unit to the right (along x), you move 3 units down (along y). So from (-6,5) your next point would be (-5,2) [when you add 1 to x-value, you subtract 3 from y-value].
To find the equation: they seem to be asking for the
y = mx + b form of a linear equation, where m is the slope and b is the y-intercept. Since they are giving you the slope (m), and a point (x- and y-value), all you need to do is plug in those values to find b, and write the equation as y = (number)x + (number)
If you find the equation before graphing, then all you need to do is plug in a value for x, which will give you a y-value, plot that point, then repeat with a different x-value.