Probability

Birth order.
A couple plans to have three children. There are 8 people arrangements of girls and boys. For example, GGN means the first two children are girls and the third child is a boy. All 8 arrangements are (approximately) equally likely.

A) Write down all 8 arrangements of the sexes of three children. What is the probability of any one of these arrangements?
B) Let X be the number of girls the couple has. What is the probability that X=2?
C) Starting from your work in (a), find the distribution of X. That is, what values can X take, and what are the probabilities for each value?

\(\displaystyle \begin{array}{*{20}c} 1 & 1 & 1 \\ 1 & 1 & 0 \\ 1 & 0 & 1 \\ 1 & 0 & 0 \\ 0 & 1 & 1 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \\ 0 & 0 & 0 \\ \end{array}\)

Now you assign G or B to the 1 or 0.

Hi tcruz,
May be it could be more useful:
Female: F
Male: M
So, I will show you four of the eight possibilitiesÑ
FFF
MMF
MFM
FMM
Can you write the rest?, can you calculate the probability?