answer with x^2 at the end

buckeyegirl33 said:
1/2x+1/4x^2-1/3 I got 3+6x-4x^2/12x^2 is it ok for it to be in this order?
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You need to learn some typing here Buckeyegirl33 . .

\(\displaystyle \frac{1}{2x} + \frac{1}{4x^2} - \frac{1}{3}\)

You can only add fractions having same denomenator.So bringing the same denomenator which is x^2 will do it ...
 
buckeyegirl33 said:
1/2x+1/4x^2-1/3 I got 3+6x-4x^2/12x^2 is it ok for it to be in this order?
Click to expand...
Hi buckeyegirl33,

\(\displaystyle \dfrac{1}{2x}+\dfrac{1}{4x^2}-\frac{1}{3}=\frac{3+6x-4x^2}{12x^2} \:\text{or} \:\dfrac{-4x^2+6x+3}{12x^2}\)

Polynomial expression are usually written in order of decreasing exponents, but in this situation, I don't see that it matters.
 
buckeyegirl33 said:
1/2x+1/4x^2-1/3 I got 3+6x-4x^2/12x^2 is it ok for it to be in this order?
Click to expand...
You MUST use brackets
1/(2x) + 1/(4x^2) - 1/3

I got (3 + 6x - 4x^2) / (12x^2)

1/2x is quite different from 1/(2x):
1/2x means 1/2 times x
1/(2x) means 1 divided by the product of 2 and x
 
buckeyegirl33 said:
is it ok for it to be in this order?

Yes, unless you've been explicitly instructed to write it differently.

Terms can always be added in any order (see: "Commutative Property of Addition").
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