Probability off on property auto crash vs. off property auto crash

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Kaboose

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Jan 11, 2013
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I have had 620 auto crashes this year.
264 have occured on company property
233 or 37.5% have occured at the home terminal
31 or .005% have occured on property non-home terminal
26.1% of a drivers day is spent on property home terminal
356 or 57.4% have occured out on the road

What is the probability percent of a driver having a crash while at the home terminal? I have no idea how to figure this out. My boss needs it asap.

Thank you
 
Kaboose said:
I have had 620 auto crashes this year.
264 have occured on company property
233 or 37.5% have occured at the home terminal
31 or .005% have occured on property non-home terminal
26.1% of a drivers day is spent on property home terminal
356 or 57.4% have occured out on the road

What is the probability percent of a driver having a crash while at the home terminal? I have no idea how to figure this out. My boss needs it asap.

Thank you
Click to expand...
I presume that the "company property" includes the "home terminal" and an area that is NOT "home terminal. You say that there were 620 auto crashes but you do NOT say how many times people drove without crashing. If you want to determine the probability of a driver having a crash, then you will need to know how many times people drove at the home terminal without a crash.
 
Drivers drove on property

HallsofIvy said:
I presume that the "company property" includes the "home terminal" and an area that is NOT "home terminal. You say that there were 620 auto crashes but you do NOT say how many times people drove without crashing. If you want to determine the probability of a driver having a crash, then you will need to know how many times people drove at the home terminal without a crash.
Click to expand...

Home terminal crashes were 233.
100 drivers X 264 days on property (22 days X 12 X 100) = 26,400
26,400 - 233 Home teminal crashes = 26,167 days no crash on home terminal.
 
Kaboose said:
Home terminal crashes were 233.
100 drivers X 264 days on property (22 days X 12 X 100) = 26,400
26,400 - 233 Home teminal crashes = 26,167 days no crash on home terminal.
Click to expand...
\(\displaystyle \dfrac{233}{26,400} < 1\%.\)

This is the probability in terms of opportunities for a crash.
 
Kaboose said:
Home terminal crashes were 233.
100 drivers X 264 days on property (22 days X 12 X 100) = 26,400
26,400 - 233 Home teminal crashes = 26,167 days no crash on home terminal.
Click to expand...
I would put units on the numbers:
233 crashes per year
26400 driver-days per year (that is, 100 drivers * 264 days/year)

The probability ratio is then 0.009 crashes per driver per day.
 
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