The players choose five numbers between 3-18. The dice is rolled three times and the numbers will be summed so the result will be between 3-18. However, in this game the dice will be rolled in total fifteen times but the same rule applies as told in the last statement, so we will have five summed up groups of numbers between 3 and 18. For example:
Dice is rolled fifteen times: 1 + 5 + 3 + 6 + 4 + 4 +2 + 1 + 6 + 6 + 5 + 1 + 4 + 2 + 5
These numbers will be now put in groups of three in the order as they were rolled and summed up:
(1 + 5 + 3); (6 + 4 + 4); (2 + 1 + 6); (6 + 5 + 1); (4 + 2 + 5) = 9; 14; 9; 12; 11.
The question is, how can I calculate the probability of the players that they have chosen five numbers between 3-18 so they are the same numbers as the summed up three number groups from dice?
Dice is rolled fifteen times: 1 + 5 + 3 + 6 + 4 + 4 +2 + 1 + 6 + 6 + 5 + 1 + 4 + 2 + 5
These numbers will be now put in groups of three in the order as they were rolled and summed up:
(1 + 5 + 3); (6 + 4 + 4); (2 + 1 + 6); (6 + 5 + 1); (4 + 2 + 5) = 9; 14; 9; 12; 11.
The question is, how can I calculate the probability of the players that they have chosen five numbers between 3-18 so they are the same numbers as the summed up three number groups from dice?