Rolling a die and getting at least.....

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ssmmss

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May 23, 2014
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1) We roll a 6-sided die 8 times. What is the probability that we get at least four “4’s”.

Any good resources out there for practice exercises similar to the one above? I want to understand it first before I try to solve it.
 
Last edited:
So this is what I came up with for the first question:

Summation i=4 to 8
8qUA8PDzkF2RHFr4TIVEJkKiEylRCZSohMJUSmfwC4NSkucXBtCwAAAABJRU5ErkJggg==
((1/6)^i) * ((5/6) ^(8-i))
 
ssmmss said:
So this is what I came up with for the first question:

Summation i=4 to 8
8qUA8PDzkF2RHFr4TIVEJkKiEylRCZSohMJUSmfwC4NSkucXBtCwAAAABJRU5ErkJggg==
((1/6)^i) * ((5/6) ^(8-i))
Click to expand...

1) \(\displaystyle \sum\limits_{k = 4}^8 {\binom{8}{k}{{\left( {\frac{1}{6}} \right)}^k}{{\left( {\frac{5}{6}} \right)}^{8 - k}}} \)
 
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