Confused About n(E). Please help

I found an exercise on a website (mentioned at the end). Below is the question which is confusing me:
Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even?
Answer is 3/4.
I can't understand how E elements make product 11. I think no any pair making product 11.
Can anyone please help?

http://www.indiabix.com/aptitude/probability/066002





I am not sure what you are asking?

E(n) does not include 11 -

neither does it include 7. Those are prime numbers.

muhammadhayat said:

I found an exercise on a website (mentioned at the end). Below is the question which is confusing me:
Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even?
Answer is 3/4.
I can't understand how E elements make product 11. I think no any pair making product 11.
Can anyone please help?.

Click to expand...

I understand the above question. But I do not understand your confusion.
The only way not to get an even product is to toss two odd numbers. There are nine odd pairs. So the answer is \(\displaystyle 1-\dfrac{9}{36}\).

muhammadhayat said:

I found an exercise on a website (mentioned at the end). Below is the question which is confusing me:
Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even?
Answer is 3/4.
I can't understand how E elements make product 11. I think no any pair making product 11.

Click to expand...

Where does the solution indicate a product of 11 or 7? I cannot see either.

Please be specific. Thank you!