You're a doctor in a town where 6 out of 100 are non smokers. The chances of stoker in smoker is 50% more than non-smoker. Now the pharmaceutical company is introducing a medicine which reduces the chances of stroke upto 1/3rd in smoker population. What is the % of the stroke population will get stroke?
What is the % of the stroke population will get stroke?
- Thread starter tharibkss
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What are your thoughts?
Please share your work with us ...even if you know it is wrong
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My calculations
Non Smokers = 6%
Smokers = 96%
Chances of non smokers getting stroke = x/6
Chances of smokers getting stroke = x/3
If by taking the drug 1/3 of smokers won't get stroke, so their chances becomes x/9
What is the % of the stroke population will get stroke? - I have no idea... I am struck here
Non Smokers = 6%
Smokers = 96%
Chances of non smokers getting stroke = x/6
Chances of smokers getting stroke = x/3
If by taking the drug 1/3 of smokers won't get stroke, so their chances becomes x/9
What is the % of the stroke population will get stroke? - I have no idea... I am struck here
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I think there must be at least one error in the above. The "%" ("percentage"?) of the stroke population which will get a stroke is 100%.
This adds up to 102%. Is this what you meant?
How did you obtain these expressions? What was your reasoning? Note: Since 1/6 is half of 1/3, you have here stated that the smokers have twice the chance (200%) of having stroke, rather than only half-again as much (150%). Was this what you meant?