Get rid of fractions here. Then substitute. Then get rid of fractions again. Then rearrange the equation to get it to a quadratic form:
I don' t have any other approach besides #37
please end this
Why are you refusing to follow suggestions? Aren't you here to learn?
i am not refusing . i already told that when i read this "clear fractions earlier to make the work easier and less error-prone." Nothing else is coming to my mind as such rather than the old steps in #40
If you don't know how to do a specific step X we are suggesting, the proper reply, assuming you want to learn, is "How do I do X?", not "please end this". If you just want the solution you can use wolframalpha or some other equation solver.
How do i do this .
How do I do what? Get rid of the fractions? Please be specific.
Making changes in #40.
I suggested a set of steps to follow instead of what you are doing in #40. If you don't know how to do a specific step, ask.
i am very well aware of what you said .
There are 2 fractions, 2 denominators. Multiple the equation by one denominator, then the other.
Multiplying by M -2
Multiply the factors on the right to get a polynomial. Simplify if you can. Then collect like terms to get a quadratic equation with M as the variable.
mx^2 - 2x^2 - 2myx = (x^2 m - 2x^2 - m^2 xy + m2xy ) + ( 2y (m^2 ) x - 4 y x m + 4 y^2 m^2 - 4ymx + 8xy - 8 m y^2 )
You have 2 terms with m^2 - finish grouping. And are there really no terms without m (constant)?
-m^2 (xy + 4 y^2) + 4myx =0
You didn't address my question about constant terms. E.g. what happened to 8xy? Also, please put the variable factor last, so it's easier for you to identify the coefficients to plug in into the quadratic roots formula.
-m^2 (xy + 4 y^2) + xy ( 4m -8) + 8m y^2 = 0
Not finished. It needs to look like a quadratic equation with m as the variable: am^2 + bm + c = 0.