natural aluminum

[logistic_guy]

Natural aluminum is all \(\displaystyle {}^{27}_{13}\text{Al}\). If it absorbs a neutron, what does it become? Does it decay by \(\displaystyle \beta^{+}\) or \(\displaystyle \ \beta^{-}\)? What will be the product nucleus?

 

[khansaheb]

Natural aluminum is all \(\displaystyle {}^{27}_{13}\text{Al}\). If it absorbs a neutron, what does it become? Does it decay by \(\displaystyle \beta^{+}\) or \(\displaystyle \ \beta^{-}\)? What will be the product nucleus?

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[logistic_guy]

Natural aluminum is all \(\displaystyle {}^{27}_{13}\text{Al}\). If it absorbs a neutron, what does it become?

Let us calculate the nuclear reaction.

\(\displaystyle {}^{27}_{13}\text{Al} + {}^{1}_{0}\text{n} \longrightarrow {}^{28}_{13}\text{Al}\)

So, it becomes \(\displaystyle \textcolor{blue}{{}^{28}_{13}\text{Al}}\)

 

[logistic_guy]

Does it decay by \(\displaystyle \beta^{+}\) or \(\displaystyle \ \beta^{-}\)?

Rule of thumb. Since I have too many neutrons than protons, I wanna get rid of some of the neutrons.

So to convert a neutron to a proton, it decays by \(\displaystyle \textcolor{blue}{\beta^{-}}\).