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does anyone know if these are correct.. especially numbers 1 and 4

1. 3x^2 + 6x - 2 = 0 3x^2 + 6x + 3 = 5 x^2 + 2x + 1 = 5/3 (x+1)^2 = sqrt(5/3) x+1 = +/-sqrt(5/3) x = -1 +/- sqrt(5/3) this is what i got but the answers don't correspond to any of the answers in my book.. what further steps do i need to take... these are the answers.. -3 +/- sqrt3/3 [-3+/-...

I think I might have solved #5.. is the correct answer: 3/2. this is how i got it.. sqrt (x+6) +sqrt 6 = sqrt 3 x+x 6 +9 2x+6 = 9 minus 6 from both sides to equal 2x=3 divide by 2 on both sides to equal x =3/2

1. solve by completing the square: -6x = 3x^2-2.. The answer I got for this is -3 +/- sqrt 3 divided by 3. is that correct? 2. solve: 1 +1/x = 12/x^2 3. simplify and rationalize the denominator: 8/[6+(2y)^1/2].. I guess the same thing would be 8/[6+ sqrt 2y] 4. solve: (w+16)^1/2 +4...

does anyone know if I did these correctly?? see my last post directly above. thanks. :D

(1.) so the answer for the first one would be 2i sqrt 5 because 2.2.5 equals 20 and the "i" is taken out for the negative. am i correct? (4.) I did the quadratic formula with a = 1, b= 3, and c = -3 -3 +/- sqrt (3)^2 - 4(1)(-3) divided by 2(1) which equals -3 +/- sqrt 9 + 12 all divided...

Sorry about that. 1. simplify: square root of -20.. so would I do the square root of 4 and the square root of 5 and multiply them together? if so, then would the answer be: -5i sqrt-2? 2. 8 divided by 6+ sqrt 2y 3. -6x=3x^2-2 (solve by completing the square) 4. solve using the...

How do I do this problem? simplify (20)^1/2.. it looks easy but I have no idea. also.... simplify and rationalize the denominator: 8/[6+(2y)^1/2 do i multiply by 6+(2y)^2? is(2y)^1/2 the same as the sqrt of 2y? how do i get started with this.. I got the first step.. I think, but not sure...

THANK YOU SOOO MUCH!!

ok.. i am still gettting the same answer for x2-7x-2=0 : [7+/(57)^1/2]/2 Would the answer for the other problem: [(64x^7y^8))/x^-8y^2]^2/3 be 8x^10y^4 ?

thank you. I got 25 b/c my book said to take 1/2 and then times by two.. that is why I was getting so confused. I have the worst book in the world. can you help with this one.. [(64x7y8))/x-8y2]2/3 I got this so far.. Since x-8 is a negative exponent, i moved it up to the top of the...

Is the answer to the first one..(x^2-6x+28)/[(x-4)(x+4)(x+1)] Im not sure if I have that negative sign right for the numerator.. in front of the 6. For the second one.. I tried doing the quadratic formula and it is not working out for me.. I just do not understand how to do this problem. Ive...

(1.) subtract: x/(x^2-16) minus 7/(x^2+5x+4): I figured out the denominators as being (x-4)(x+4) and (x+1)(x+4) consecutively. (2.) Find the x-intercepts of this quadratic function: y+2x^2-10x-72. this is what I did so far. 2x^2/2 - 10x/2=72/2 x^2-5x^2 (25) = 36 x^2-10x+25+61 ...

thanks soo much!!!

ok.. I think I am halfway there with this problem.. I got the following answer.. 6a+3h-2a^2-h^2 now what do i do?

Ok.. what does ^ mean.. I never saw this symbol before in my book. I am still trying to figure this one out. When you did f(a) = 4 + 3a-a^2.. would I do the same for f(h) (i.e) 4 + 3h -h^2.. ??? number 2 is correct... thanks.. I did substitute and I got 27/2 = 27/2 number 3.. I guess...

(1.) given f(x) = 4 + 3x - x ^ 2, find and simplify f(a+h) - f(a) I have no idea how to even begin this one. (2.) this one is absolute value: |8-q| = |q +19|.. I tried to figure this one out and I got -11/2.. is this correct? the other two options were.. no solution, or -11/2, 0...