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1. solve by completing the square: -6x = 3x^2-2.. The answer I got for this is -3 +/- sqrt 3 divided by 3. is that correct? 2. solve: 1 +1/x = 12/x^2 3. simplify and rationalize the denominator: 8/[6+(2y)^1/2].. I guess the same thing would be 8/[6+ sqrt 2y] 4. solve: (w+16)^1/2 +4...

How do I do this problem? simplify (20)^1/2.. it looks easy but I have no idea. also.... simplify and rationalize the denominator: 8/[6+(2y)^1/2 do i multiply by 6+(2y)^2? is(2y)^1/2 the same as the sqrt of 2y? how do i get started with this.. I got the first step.. I think, but not sure...

(1.) subtract: x/(x^2-16) minus 7/(x^2+5x+4): I figured out the denominators as being (x-4)(x+4) and (x+1)(x+4) consecutively. (2.) Find the x-intercepts of this quadratic function: y+2x^2-10x-72. this is what I did so far. 2x^2/2 - 10x/2=72/2 x^2-5x^2 (25) = 36 x^2-10x+25+61 ...

(1.) given f(x) = 4 + 3x - x ^ 2, find and simplify f(a+h) - f(a) I have no idea how to even begin this one. (2.) this one is absolute value: |8-q| = |q +19|.. I tried to figure this one out and I got -11/2.. is this correct? the other two options were.. no solution, or -11/2, 0...