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A bit confused again So the variance of the estimator of P_c was σ2=0,000542 = 0,00000029 And the variance for the expected number bankruptcies was σ2=17,262= 297,91. or was it the other way around??

Ahh I see! Thanks man, much appreciated!

Thanks DrPhil, it makes sense now. One more question before I start working on those confidence intervals: Discuss the extent to which these assumptions are likely to be met in practice. Not sure if I understand this question correctly. I am to prove the 3 criteria for a binomial...

Ohh, I see. So the variance for the estimate PC is: σ/√n = 29,9/√3 = 17,26 = std dev σ2=17,262= 297,91. And the variance for the expected number bankruptcies is: 0,00093/√3 = 0,00054 σ2=0,000542 = 0,00000029 Is this correct? I'm just a little unsure about why we put in 3 for sample size. I...

Thanks for the reply. Much appreciated! :) Hmm, I'm not sure. I'm really bad at statistics, but hoping I'll improve soon enough, but why exactly do we have to divide it by sqrt(3)? Don't we assume every year to have 920 bankruptcies a year? The text says "These figures are considered to be...

Anyone?? I just need a little push with the estimates to get started. I think I got them wrong.

So I've translated this assignment from another language, but hope it's good enough translated/understandable. 1. The problem statement, all variables and given/known data According to the Statistics of Sweden, there was in the construction sector in the period 2009-2011 an average of 920...