How does theta change with psi?
I've tried solving it this way:
Which led me to the equation: r+40e\sin\theta=(e+r)\sin(\psi-\theta)
But I simply don't know how to proceed.
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.