What is the rate of change of the volume of a ball
V=(4/3)* π * r^3
with respect to the radius when the radius is equals=4?
V=(4/3)* π * r^3
with respect to the radius when the radius is equals=4?
The volume changes at a rate of?
(Type an exact answer, using pi as needed.)
So i started with
r = 4, insert into the equation.
V=(4/3)*pi*r^3
V= (4/3)*pi*(4)^3
V= 4/3*pi* 64
Then, slope of the curve at point (r,V)
lim h->0 f(r+h)-f(r)/h
=lim h->0 (f(4+h) - (4/3*pi*64))/h
=lim h->0 ((4/3*pi (4+h)^3) -
(4/3*pi*64))/h
am I on the right track?
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