NoahSilva2
New member
- Joined
- Sep 20, 2017
- Messages
- 4
I need help solving this one problem assigned for homework in my Algebra II HOnors class.
Let f(x)=ax^2+bx+c such that
f(0)=f(1)
f(2)=2f(1)
f(3)=16
Calculate f(-1)
I'm lost, and have no idea where to start. All I've been able to work out is that -a=b because
f(0)=f(1)
f(0)=a(0)^2+b(0)+c
f(0)=c
f(1)=a(1)^2+b(1)+c
f(1)=a+b+c
a+b+c=c
a+b=0
-a=b
Let f(x)=ax^2+bx+c such that
f(0)=f(1)
f(2)=2f(1)
f(3)=16
Calculate f(-1)
I'm lost, and have no idea where to start. All I've been able to work out is that -a=b because
f(0)=f(1)
f(0)=a(0)^2+b(0)+c
f(0)=c
f(1)=a(1)^2+b(1)+c
f(1)=a+b+c
a+b+c=c
a+b=0
-a=b
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