0.999... = 1

Agent Smith

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So I was exploring the kiddie section of math and encountered this:

3.0013849483127...
and
2.9986150516872...

We add these two and get 5.9999999999999... = 5.95.\overline 9

I "know" that 0.9=10.\overline 9 = 1. So 5.9=5+1=6=3.0013849483127...+2.9986150516872...5.\overline 9 = 5+ 1 = 6 = 3.0013849483127... + 2.9986150516872...

This is the first problem I've worked on where 0.9=10.\overline 9 = 1 shows up. It's a special result for me therefore. Question: How often does this happen in math? Is it trivial, commonplace or is it rare and should I dig a little deeper into the matter?
 
You cannot know what the dots stand for. They indicate some limit, and as soon as you calculate with limits instead of written numbers, the 0.9ˉ 0.\bar 9 and alike will disappear. So, yes, it is rare since we usually speak about limits instead of dots.
 
🤔

Have you ever encountered a number like 5.999...=5.95.999... = 5.\overline 9 in your mathematical life? If yes, where exactly?

Also, correct, n=1910n=1\displaystyle \sum_{n = 1} ^\infty \frac{9}{10^n}= 1, but in my experience, to get a result like 5.999...5.999... is once a blue moon.
 

In school. I played around with what periods mean, i.e. divisions by ##3,6,7,9,11## and so on, and in online forums where kids discuss whether 0.9ˉ 0.\bar 9 and 11 are equal or not.

Also, correct, n=1910n=1\displaystyle \sum_{n = 1} ^\infty \frac{9}{10^n}= 1, but in my experience, to get a result like 5.999...5.999... is once a blue moon.

This formula means n=1910n=limnk=1n910k=1,\displaystyle \sum_{n = 1} ^\infty \frac{9}{10^n}= \lim_{n \to \infty}\sum_{k = 1} ^n \frac{9}{10^k}=1, i.e. it is a limit and a limit is a unique number - so it exists. The question about the deficits of the decimal system (or any other) doesn't occur in mathematics. It's only a notational artifact.

I even like to say, that mathematicians actually only need very few numbers: {±2,±1,0,π,e,i}. \{\pm 2 ,\pm 1,0,\pi ,e , i\}. Everything else are examples. 3 3 is already physics. Or number theory: there you need 3,4 3,4 and 5. 5. ;)
 
In school. I played around with what periods mean, i.e. divisions by ##3,6,7,9,11## and so on, and in online forums where kids discuss whether 0.9ˉ 0.\bar 9 and 11 are equal or not.



This formula means n=1910n=limnk=1n910k=1,\displaystyle \sum_{n = 1} ^\infty \frac{9}{10^n}= \lim_{n \to \infty}\sum_{k = 1} ^n \frac{9}{10^k}=1, i.e. it is a limit and a limit is a unique number - so it exists. The question about the deficits of the decimal system (or any other) doesn't occur in mathematics. It's only a notational artifact.

I even like to say, that mathematicians actually only need very few numbers: {±2,±1,0,π,e,i}. \{\pm 2 ,\pm 1,0,\pi ,e , i\}. Everything else are examples. 3 3 is already physics. Or number theory: there you need 3,4 3,4 and 5. 5. ;)
Gracias for the correction. I should've said limnk=1n910k=1\displaystyle \lim_{n \to \infty} \sum_{k = 1} ^n \frac{9}{10^k} = 1.
 
Gracias for the correction. I should've said limnk=1n910k=1\displaystyle \lim_{n \to \infty} \sum_{k = 1} ^n \frac{9}{10^k} = 1.
No need to. The notation n=1 \displaystyle{\sum_{n=1}^\infty } is totally ok.

I just wanted to emphasize that it is a limit. I have often heard / read / seen that kids think a limit is something that tends to something. But the limit itself is a number, nothing that tends. It is fixed. And as such, 0.999 0.999\ldots does not tend towards 1. 1. It is one.

0.999 0.999\ldots is - as you already correctly mentioned - only another way to write n=1910k \displaystyle{\sum_{n=1}^\infty } \dfrac{9}{10^k} and that equals one. My comment about numbers was partly meant as a joke, but it has something true in it. The specific representation of numbers doesn't play a big role in mathematics. It is a short chapter on how decimal, binary, octal, hexadecimal, or whatever basis is used are written. Here is a nice list:
You will see that most people have always used fingers and toes as a basis. However, the Babylonian 60 60 is still present in our hours, minutes, and the calendar.
 
S=0.999S=0.99\overline{9}10S=9.99910S=9.99\overline{9}_____subtract
9S=99S=9 _____divide
S=1S=1
 
S=0.999S=0.99\overline{9}10S=9.99910S=9.99\overline{9}_____subtract
9S=99S=9 _____divide
S=1S=1
It should be, I think, 10×0.9=9.910 \times 0.\overline 9 = 9. \overline 9
 
There are infinitely many examples, so to have seen one before is not very likely,
4.99999..., 5.999999..., 6.99999...., .... 97.99999, 314.99999..., and my favorite one: 273.9999999.....
How about -43.9999999.99999....?
 
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