bedigursimran
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- Joined
- Sep 12, 2017
- Messages
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The folium of Descartes has the graph shown below in Figure 1, the Cartesian equation is x^3 + y^3 = 3xy
Use the substitution y/x = t to find the parametric equation of the folium.
The problem that I have with it is understanding how to go about doing it. Like can I substitute in y = tx (rearranged y/x=t) in the equation of folium?
Which gives.
x^3 + (tx)^3 = 3tx^2
=> x^2 + (t^3)(x^2) = 3tx
Is that right? If so, how do I turn it into a parametric equation?
Thanks guys!! I am really confused guys.
Use the substitution y/x = t to find the parametric equation of the folium.
The problem that I have with it is understanding how to go about doing it. Like can I substitute in y = tx (rearranged y/x=t) in the equation of folium?
Which gives.
x^3 + (tx)^3 = 3tx^2
=> x^2 + (t^3)(x^2) = 3tx
Is that right? If so, how do I turn it into a parametric equation?
Thanks guys!! I am really confused guys.