Hello, its my first question here. I need a help with a problem:
i have this equality 2logx = 4-log(x/10)
I did this:
2log10 x = 4 - log10 X - log10 10 (Log properties(log(X/Y) = logX - logY))
log10 x2 = 4 - log10 X - 1 (Log10 = 1)
log10 x2 = 3 - log10 X
log10 x2 + log10 X = 3
log10X3 = 3 (Log properties (log(XY) = logX + logY))
(log10X3)10 = 103 (Cancel the logarithm)
X3 = 103
X = 3√ 103
X = 10 (THIS IS MY FIRST SOLUTION)
I don't know if this is a right solution, but i found another solution later, doing again this:
2logx = 4-log(x/10)
log10X2 - log10 (X/10) = 4
(log10 (X3/10)) = 4
(log10(X3/10))10 = 104
X3/10 = 104 * 10
X3 = 3√ 105
X = 103√ 100 (SECOND SOLUTION)
What of the 2 solutions is correct? This is an exam, i don't know what to do :'(.
Thanks for all guys.
i have this equality 2logx = 4-log(x/10)
I did this:
2log10 x = 4 - log10 X - log10 10 (Log properties(log(X/Y) = logX - logY))
log10 x2 = 4 - log10 X - 1 (Log10 = 1)
log10 x2 = 3 - log10 X
log10 x2 + log10 X = 3
log10X3 = 3 (Log properties (log(XY) = logX + logY))
(log10X3)10 = 103 (Cancel the logarithm)
X3 = 103
X = 3√ 103
X = 10 (THIS IS MY FIRST SOLUTION)
I don't know if this is a right solution, but i found another solution later, doing again this:
2logx = 4-log(x/10)
log10X2 - log10 (X/10) = 4
(log10 (X3/10)) = 4
(log10(X3/10))10 = 104
X3/10 = 104 * 10
X3 = 3√ 105
X = 103√ 100 (SECOND SOLUTION)
What of the 2 solutions is correct? This is an exam, i don't know what to do :'(.
Thanks for all guys.