NoahSilva2
New member
- Joined
- Sep 20, 2017
- Messages
- 4
Solve the system of equations for x and y.
x2+4y2-8y=4
y2-2y-8x-16=0
This question was a bonus question I got lost on a test in my Algebra II Honors class.
So far, I've worked out that you need to subtract 4 from each side of the first equation to get the system of
x2+4y2-8y-4=0
y2-2y-8x-16=0
From here I know I need to factor, but we haven't learned yet how to factor quadrinomials with more than one variable. (Learned to factor by the box method)
Because the equations are equal to zero, I have a feeling there are two different solutions. I just dunno how to factor them.
Any help would be appreciated!
Thank you,
~NS2
x2+4y2-8y=4
y2-2y-8x-16=0
This question was a bonus question I got lost on a test in my Algebra II Honors class.
So far, I've worked out that you need to subtract 4 from each side of the first equation to get the system of
x2+4y2-8y-4=0
y2-2y-8x-16=0
From here I know I need to factor, but we haven't learned yet how to factor quadrinomials with more than one variable. (Learned to factor by the box method)
Because the equations are equal to zero, I have a feeling there are two different solutions. I just dunno how to factor them.
Any help would be appreciated!
Thank you,
~NS2