I have two integrals, and I need to prove the first one is equal to the second using the substitution x=sqrt(u). Here is the answer I got, but am unsure of my algebra to transform the function to sqrt(1+1/4u).
I have two integrals, and I need to prove the first one is equal to the second using the substitution x=sqrt(u). Here is the answer I got, but am unsure of my algebra to transform the function to sqrt(1+1/4u).
Last edited by mmm4444bot; 12-02-2017 at 09:25 PM. Reason: Imported image
We're going to struggle, here, with "is equal to".
1) We should notice that the Domains are different. The 1/(4x) integrand has a big hole in it. Maybe we mean "is equal to" only for Positive Real Numbers?
2) Really, our only hope of claiming these two integrals are equal is if they differ by only a constant. That doesn't quite sound "equal", does it? Ponder why an integral which evaluates to [tex]\cos^{2}(x) + C[/tex] is EXACTLY the same as an integral that evaluates to [tex]\sin^{2}(x) + D[/tex].
3) You started your problem with [tex]x = \sqrt{u}[/tex]. You ended your demonstration with [tex]x = u[/tex]. That's no good.
Good work. Give it some more thought. In particular, think about whether it CAN be true before spending a lot of time trying to prove it.
"Unique Answers Don't Care How You Find Them." - Many may have said it, but I hear it most from me.
Well, then I guess you're done. Just heed comment #3.
"Unique Answers Don't Care How You Find Them." - Many may have said it, but I hear it most from me.
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