Not sure what I'm doing wrong...
Why do you think that you're doing something wrong?
Your image is sideways (hard to read) and
waaaaaaay too small. I
think the written portion of the image says the following:
d)
right solid
Area of bases --> 24 x 2 = 48
8+2
. . . . . . . . .= 2pi[something]
2 (2) = 12.56
A = pi (26+)
2 = 2x
(1+2)
6 x 4 = 24
5+4
Area of book --> 20
62 2
2 = 40
102
S
24ft
2 = 20ft
2
Area of cylinder --> 91.4
ft2
half [something] circum. (2pi[something])/(3a2) = 6.28
ft x 5 = 31.4
2t
SKS = 6 x 5(2) = 60
ft2
91.4 + 40 + 12.6 + 48
ft2 = 191.96
ft2
Naturally, we're having a bit of difficulty with this. :shock:
You don't include the original exercise (such as the instructions); would the following be a correct statement of the question?
The shape shown below is the top view of a right solid:
Code:
top view:
+---------+..
| | `.
|4' | |
| | ,'
+---------+''
6'
The solid has a height of five feet. (Note: All units are in "feet".) The rounded portion at the right of the above shape is a semicircle with radius two feet.
Given this information, find the surface area of the solid.
If not, please reply with corrections and clarifications. If so, then:
There are two rectangular areas (one on the top and one on the bottom) of this prism. Use the given length (6') and depth (4') to find the area of one of these rectangles, and then multiply by 2. Keep track of this by labelling this portion as, say, "top & bottom rectangles".
There is one semicircular area on the diagram of the top of the prism; there is a corresponding one on the bottom. Together, these make one circle with the given radius (2'). Plug this into the formula for the area of a circle. (Do NOT round the result! Keep it in terms of "pi"!) Keep track of this value by labelling it as, say, "circular area".
On the left-hand side of the drawing is a line which represents a vertical "side" of the wrap-around portion of this solid (being the part that is not the bottom of the solid and is the part that we cannot see in the drawing). You have a depth (4') and a height (5') for this rectangular area. Plug these dimensions into the formula for the area of a rectangle. Keep track of this value by labelling it, say, "left-hand side".
On the "upper edge" in the drawing, you have another vertical "side". What is the length of this? What is the height of this? What value does this then give you for the area of that rectangular side? How does this relate to the area of the rectangular side represented by the "lower edge" in the drawing? Keep track of this by labelling it, say, "upper & lower rectangles".
The remainder of the unseen wrap-around is half of the side-surface-area of a cylinder with radius 2' and height 5' (that is, it is the part of the surface area which does not include the end-caps). Plug these values into the formula for the side-surface-area of a right circular cylinder, and divide by two to get the area you need. Label this as, say, "cylindrical part".
Add the values, keeping everything exact (that is, in terms of "pi", not decimal round-offs). What do you get?
If you get stuck, please reply with a clear listing of your steps and results in following the above step-by-step instructions. Thank you!