Riddle:
You are in a small labyrinth.
There are 4 ways around you.
At the end of each way there is a room.
Three of four rooms are empty, while 4th have exit from the labirynth.
One empty room what is opposide to the room with exit is always red color.
During one average labyrynth run, how many rooms you will met before finding exit?
I'm not good in probability, I have tried to solve this and I'm stuck at this part.
And I think it's
(100% + 50% + 50% + 33%) / 4 = 58,33% of rooms
But also:
In 4 possible solutions we entered a total of 8 rooms, and in 4 solutions there are 16 rooms in total. So 8 / 16 = 50% of rooms
I need's your help.
You are in a small labyrinth.
There are 4 ways around you.
At the end of each way there is a room.
Three of four rooms are empty, while 4th have exit from the labirynth.
One empty room what is opposide to the room with exit is always red color.
During one average labyrynth run, how many rooms you will met before finding exit?
I'm not good in probability, I have tried to solve this and I'm stuck at this part.
And I think it's
(100% + 50% + 50% + 33%) / 4 = 58,33% of rooms
But also:
In 4 possible solutions we entered a total of 8 rooms, and in 4 solutions there are 16 rooms in total. So 8 / 16 = 50% of rooms
I need's your help.
Last edited: