How to calculate the value of 'n'? ∫dx/√(2ax - x² ) = a^n sin^-1[(x/a) -1]
∫dx/√(2ax - x² ) = a^n sin^-1[(x/a) -1] I don't understand the equation. Could you simplify the equation here and tell me how to calculate the value of 'n'?
∫dx/√(2ax - x² ) = a^n sin^-1[(x/a) -1] I don't understand the equation. Could you simplify the equation here and tell me how to calculate the value of 'n'?
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