How do you know that 'x' in equation 1 is same as that 2?Hi,
I have the following problem:
1. 27.5% = ((25+x)/(121+x))
2. 30.0% = ((43-x)/(121+x))
Im having issues solving for x that satisfy both the 27.5% and the 30%.
Please let me know of any structures I should be following.
Thanks!
Do you "see" that (25+x)/.275 = (43-x)/.3 ?1. 27.5% = ((25+x)/(121+x))
2. 30.0% = ((43-x)/(121+x))
0.275= (25+ x)/(121+ x)Hi,
I have the following problem:
1. 27.5% = ((25+x)/(121+x))
0.30= (43- x)/(121+ x)2. 30.0% = ((43-x)/(121+x))
That is because there is no value of x that satisfies both equations.Im having issues solving for x that satisfy both the 27.5% and the 30%.
Please let me know of any structures I should be following.
Thanks!
No such number exists.Hi,
I have the following problem:
1. 27.5% = ((25+x)/(121+x))
2. 30.0% = ((43-x)/(121+x))
Im having issues solving for x that satisfy both the 27.5% and the 30%.
Please let me know of any structures I should be following.
Thanks!
A big cup of coffee for you while you stand in the corner?Do you "see" that (25+x)/.275 = (43-x)/.3 ?
I'm purty good at jumping to conclusions!A big cup of coffee for you while you stand in the corner?
Actually, it is a rather subtle mistake. I scratched my head over your response for quite a few minutes wondering whether I was wrong.I'm purty good at jumping to conclusions!
Anyhoo, I'll have company: both of Halls' solutions are wrong :cool:
With a pun that awful, maybe SK is the one who needs the corner!and me too....
Denis ... go stand in the corner and don't Khan-fuse me like this ... ever again ...