Hello everyone!
The equation that I'm sketching a graph for is: y = (x+3)(x+2)(x-1) at -4.5 ≤ x ≤ 4.5
I've already found x and y intercepts, and derived the equation (y' = 3x^2 + 8x + 1)
I've used the quadratic formula to find the x-values of the original equations turning points, but the y-values are where I'm getting stuck.
I originally subbed in the x-values into the derived equation, but when I check my answers against the turning point co-ordinates on my graphics calculator, they're not even close.
This is my working for the x-values:
These are my answers for the y-values when subbing in each x-value:
...and these are the co-ordinates for the turning points:
So I've got the x-values right, but I have no idea how to find the y-values now.
What am I doing wrong?
The equation that I'm sketching a graph for is: y = (x+3)(x+2)(x-1) at -4.5 ≤ x ≤ 4.5
I've already found x and y intercepts, and derived the equation (y' = 3x^2 + 8x + 1)
I've used the quadratic formula to find the x-values of the original equations turning points, but the y-values are where I'm getting stuck.
I originally subbed in the x-values into the derived equation, but when I check my answers against the turning point co-ordinates on my graphics calculator, they're not even close.
This is my working for the x-values:
These are my answers for the y-values when subbing in each x-value:
...and these are the co-ordinates for the turning points:
So I've got the x-values right, but I have no idea how to find the y-values now.
What am I doing wrong?