dannywmarino
New member
- Joined
- Dec 7, 2018
- Messages
- 1
The figure below shows a square ABCD and an equilateral triangle DPC:
Ted makes the chart shown below to prove that triangle APD is congruent to triangle BPC:
Ted makes the chart shown below to prove that triangle APD is congruent to triangle BPC:
Statements | Justifications |
---|---|
In triangles APD and BPC; DP = PC | Sides of equilateral triangle DPC are equal |
In triangles APD and BPC; AD = BC | Sides of square ABCD are equal |
Angle ADC = angle BCD = 90° so angle ADP = angle BCP = 30° | |
Triangles APD and BPC are congruent | SAS postulate |
Which of the following completes Ted's proof?
In square ABCD; angle ADC = angle BCD In square ABCD; angle ADP = angle BCP In triangles APD and BPC; angle ADC = angle BCD In triangles APD and BPC; angle ADP = angle BCP
Last edited by a moderator: