The Jacobian and area differential

Win_odd Dhamnekar

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How to sketch several coordinate curves of the given coordinate system to form a grid of "rectangles" (i.e., make sure the u-curves are close enough to appear straight between the v-curves and vice-versa. How to find the area differential and discuss its relationship to the "coordinate curve grid". The following are the linear transformations and have a constant jacobian determinant.

1)Elliptic coordinates \(\displaystyle T(u,v)=\langle \cosh{u} \cos{v},\sinh{u} sin{v}\rangle\)

2)Bipolar coordinates \(\displaystyle T(u,v)=\langle \frac{\sinh{v}}{\cosh{v} \cos{u}},\frac {\sin{u}}{\cosh{v}\cos{u}}\rangle\)

Answer : 1)The area differential of elliptic coordinates is \(\displaystyle (\sinh^2{u}cos^2{v} + \cosh^2{u}\sin^2{v})dudv\) But how to sketch coordinate curves of the given cordinate system?

2) The area differential of bipolar coordinates is \(\displaystyle \bigg(\frac{\sinh^2{v}\sin^2{u}}{(\cosh{v}-\cos{u})^4}-\bigg((\frac{\cosh{v}}{(\cosh{v}-\cos{u})}-\frac{\sin^2{v}}{(\cosh{v}-\cos{u})^2}) (\frac{\cos{u}}{\cosh{v}-cos{u}}-\frac{\sin^2{u}}{(\cosh{v}-\cos{u})^2})\bigg)\bigg) du dv\)

How to sketch coordinte curves of the given coordinate system?
 
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How to sketch several coordinate curves of the given coordinate system to form a grid of "rectangles" (i.e., make sure the u-curves are close enough to appear straight between the v-curves and vice-versa. How to find the area differential and discuss its relationship to the "coordinate curve grid". The following are the linear transformations and have a constant jacobian determinant.

1)Elliptic coordinates \(\displaystyle T(u,v)=\langle \cosh{u} \cos{v},\sinh{u} sin{v}\rangle\)

2)Bipolar coordinates \(\displaystyle T(u,v)=\langle \frac{\sinh{v}}{\cosh{v} \cos{u}},\frac {\sin{u}}{\cosh{v}\cos{u}}\rangle\)

Answer : 1)The area differential of elliptic coordinates is \(\displaystyle (\sinh^2{u}cos^2{v} + \cosh^2{u}\sin^2{v})dudv\) But how to sketch coordinate curves of the given cordinate system?

2) The area differential of bipolar coordinates is \(\displaystyle \bigg(\frac{\sinh^2{v}\sin^2{u}}{(\cosh{v}-\cos{u})^4}-\bigg((\frac{\cosh{v}}{(\cosh{v}-\cos{u})}-\frac{\sin^2{v}}{(\cosh{v}-\cos{u})^2}) (\frac{\cos{u}}{\cosh{v}-cos{u}}-\frac{\sin^2{u}}{(\cosh{v}-\cos{u})^2})\bigg)\bigg) du dv\)

How to sketch coordinte curves of the given coordinate system?
Hi, what have you tried? Where are you stuck? Please tell us exactly what you need help with so we can help. Thank you.
 
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