How did you prove that (a+b+c) is greater than 6?We have a triangle with sides a, b, c that ab+bc+ca=12
Prove that 6=<a+b+c<7
I proved that a+b+c is no less than 6 but how to prove that it's less than 7?
We have a triangle with sides a, b, c that ab+bc+ca=12
Prove that 6=<a+b+c<7
I proved that a+b+c is no less than 6 but how to prove that it's less than 7?
TO eligotas, If you will answer Prof Khan's question then I will show why the upper bound.How did you prove that (a+b+c) is greater than 6?
Please share your work - indicating exactly where you are stuck.