11plus 3 times the square root of 7x-9 equals 14
- Thread starter Serene
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- Apr 12, 2005
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Re: Please Help
\(\displaystyle 11 + 3 \cdot \sqrt{7x-9}\;=\;14\)
\(\displaystyle 3 \cdot \sqrt{7x-9}\;=\;3\)
Whoops! You wandered off already. How did you get NEGATIVE 3?
Divide by 3.
Square.
Add 9.
Divide by 7.
Check your answers.
\(\displaystyle 11 + 3 \cdot \sqrt{7x-9}\;=\;14\)
\(\displaystyle 3 \cdot \sqrt{7x-9}\;=\;3\)
Whoops! You wandered off already. How did you get NEGATIVE 3?
Divide by 3.
Square.
Add 9.
Divide by 7.
Check your answers.