2 questions

G

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1. For every integer K from 1-10, inclusive, the Kth term of a certain sequence is given by (-1)^k+1 (1/2k). If T is the sum of the first 10, then T equals what?


2. This is the information regarding the number of days a salesperson worked during a 3-month period: June: 20 days, July: 17 days, August: 19 days. This sales person made 168 sales calls during this 3-month period. If the number of calls is proportional to the number of days worked, how many sales calls did the salesperson make in the month of August?


Can you please show the precedures to find the answers to both questions? I got 56 as the result to question 2, but I'm not sure it's right.
 
For the first problem, do you mean \(\displaystyle \frac{1}{2}k\) or \(\displaystyle \frac{1}{2k}\)? Just want to make sure.

As for number 2, I believe it's 57. The calls are 3 to 1. 19*3=57.
 
alejandra9kg said:
1. For every integer K from 1-10, inclusive, the Kth term of a certain sequence is given by (-1)^k+1 (1/2k).
Click to expand...
That's simply k/2 if k even, -k/2 if k odd : understand?

Next time, show (1/2k) as (1/2)k or k/2.
 
I have to disagree with Denis.
What you wrote
(-1)^k+1 (1/2k)
is
(-1)^k+1*k/2 =
(-1)^k+k/2
That would be
-1+1/2 +1+2/2 -1+3/2... =
(1/2)(1+2+3...+10)

I suspect you mean
((-1)^k+1)*(k/2)
That would be
k if k is even and
0 if k is odd or
2+4+6+8+10
 
(-1)^k+1 (1/2k).

Geezzzz; I meant to remove the 2nd "1" since it was not necessary,
and somehow wrote down (-1)^k(1/2k).; like, I removed "+1" :cry:

Thanks, Gene...my 1st mistake this year :shock:
 
Denis said:
my 1st mistake this year
Click to expand...
I don't bother counting on a yearly basis; weekly, even daily, counts are embarrassing enough! :wink: :lol:

Eliz.
 
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