NOTE: d = degrees
If sec (3x - 10)d = csc (x + 40)d, then a possible value of x is
1) 25
2) 15
3) 55
4) 65
MY WORK:
3x - 10 = x + 40
After doing the algebra, my answer is x = 25, which is choice one above.
The book's answer is x = 15, which is choice 2.
What is the correct method to solve this question? Am I not suppose to solve for x using algebra?
If sec (3x - 10)d = csc (x + 40)d, then a possible value of x is
1) 25
2) 15
3) 55
4) 65
MY WORK:
3x - 10 = x + 40
After doing the algebra, my answer is x = 25, which is choice one above.
The book's answer is x = 15, which is choice 2.
What is the correct method to solve this question? Am I not suppose to solve for x using algebra?