(1-1/x+2)/1+2/x-1 Is the LCD (x+2)(x-1)? And for my answer I put down-2/3x+6, is this right?
J jshaziza Junior Member Joined Jan 26, 2007 Messages 102 May 18, 2007 #1 (1-1/x+2)/1+2/x-1 Is the LCD (x+2)(x-1)? And for my answer I put down-2/3x+6, is this right?
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 May 18, 2007 #2 Your posting is difficult to decipher. Have you considered LaTex. Is this what you mean?: \(\displaystyle \L\\\frac{1-\frac{1}{x+2}}{1+\frac{2}{x-1}}\) If so, it's equivalent to \(\displaystyle \L\\\frac{\sout{x+1}}{x+2}\cdot\frac{x-1}{\sout{x+1}}=\frac{x-1}{x+2}\)
Your posting is difficult to decipher. Have you considered LaTex. Is this what you mean?: \(\displaystyle \L\\\frac{1-\frac{1}{x+2}}{1+\frac{2}{x-1}}\) If so, it's equivalent to \(\displaystyle \L\\\frac{\sout{x+1}}{x+2}\cdot\frac{x-1}{\sout{x+1}}=\frac{x-1}{x+2}\)
